var mobile = $('#mobile').val();
var pwd = $('#pwd').val();
$.ajax({
url: logincheck.php',
type: 'POST',
dataType: 'json',
data:({
mobile : mobile ,
pwd : pwd
}),
error: function(){
alert('Error loading');
},
success: function(data){ if(data.logged_in) {
// here you can do with your logic .}else{
// login error :)}}
}
// see the logincheck.php where we send json format data to json header.
$name = "sir";
$mobile = "9406381901";
$email = "manoj.pali@georeachonline.com";
$logged_in= "logged_in";
$data = array( "name" => $name, "mobile" => $mobile, "email" => $email, "logged_in" => $logged_in);
// header('Content-type: application/json');
// Return JSON
echo json_encode($data);
JavaScript Nesne Bildirimi
- Giriş
- Yapılandırma/Kurulum
- Öntanımlı Sabitler
- JSON İşlevleri
- json_decode — Bir JSON dizgesini çözümler.
- json_encode — Değerin JSON karşılığını verir.
- json_last_error — Oluşan son hatayı döndürür.
manojpali at live dot com
23-May-2012 10:28
jitendra dot thakur2008 at gmail dot com
18-Nov-2011 02:24
JSON is used where we want send data as an object its either be an array or string.
jquery and php json example
var dataString = 'comment=' + comment;
$.ajax({
type: "POST",
url: "pagepostbyajax.php",
//this data is mendetory when u want post data when posting page by ajax.
//after that ur data send to that page. now in backend page echo json data.if your //data is in array format the use json_encode() function then echo that json data
//now you find tht json in your success that can you use by taking a loop.
data: dataString,
cache: false,
datatype: json,
success: function(html){
$("ul#update").append(datal);
alert(data);
}
});
Regards Jitendra Thakur
